Originally Posted by Yellow Boler
I just thought of another way
5x + 5x + 5x =90
2y + 2y + y =25
,3z = 18
Y + 3X x z = Ans
X = 6
Y = 5
Z = 6
Ans = 5 + 18 x 6 = 113
If it's just about the number of tires
It helps to think of pictures as abstract constructs.
The first equation has three identical somethings equal to 90, so each of those identical somethings is 30. So far so good.
The second equation requires an assumption that the first two somethings have twice the value of the third something. This is where the abstraction breaks down. You have to assume they are representations of real world trailer tires
.(That felt a little unfair, but I’ll let it pass…) So, five (presumed) identical tires
is 25, making each tire each tire 5.
The third equation is straightforward like the first. Three somethings is 18, so each something is 6.
Finally, one must notice in the last equation that the second something (call it a trailer if you like) is not exactly the same as the similar somethings in the first equation. It’s missing several somethings that can be quantified by the previous equations.
By the way, I would argue is cannot be only
about the tires
, because the third picture has no tires, so it could not have a defined value of 18 (or anything else). Your assumption creates a logical contradiction.